On the spectrum of the pencil of high order differential operators with almost periodic coefficients
In this paper, the spectrum and the resolvent of the operator L λ which is generated by the differential expression ℓ λ ( y ) = y ( m ) + ∑ γ = 1 m ( ∑ k = 0 γ λ k p γ k ( x ) ) y ( m − γ ) has been investigated in the space L 2 ( R ) . Here the coefficients p γ k ( x ) = ∑ n = 1 ∞ p γ k n e i α n x...
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Veröffentlicht in: | Boundary value problems 2015-12, Vol.2015 (1), p.1-19, Article 238 |
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Format: | Artikel |
Sprache: | eng |
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Zusammenfassung: | In this paper, the spectrum and the resolvent of the operator
L
λ
which is generated by the differential expression
ℓ
λ
(
y
)
=
y
(
m
)
+
∑
γ
=
1
m
(
∑
k
=
0
γ
λ
k
p
γ
k
(
x
)
)
y
(
m
−
γ
)
has been investigated in the space
L
2
(
R
)
. Here the coefficients
p
γ
k
(
x
)
=
∑
n
=
1
∞
p
γ
k
n
e
i
α
n
x
,
k
=
0
,
1
,
…
,
γ
−
1
;
p
γ
γ
(
x
)
=
p
γ
γ
,
γ
=
1
,
2
,
…
,
m
, are constants,
p
m
m
≠
0
and
p
γ
k
(
ν
)
(
x
)
,
ν
=
0
,
1
,
2
,
…
,
m
−
γ
, are Bohr almost-periodic functions whose Fourier series are absolutely convergent. The sequence of Fourier exponents of coefficients (these are positive) has a unique limit point at +∞. It has been shown that if the polynomial
ϕ
(
z
)
=
z
m
+
p
11
z
m
−
1
+
p
22
z
m
−
2
+
⋯
+
p
m
−
1
,
m
−
1
z
+
p
m
m
has the simple roots
ω
1
,
ω
2
,
…
,
ω
m
(or one multiple root
ω
0
), then the spectrum of operator
L
λ
is pure continuous and consists of lines
Re
(
λ
ω
k
)
=
0
,
k
=
1
,
2
,
…
,
m
(or of line
Re
(
λ
ω
0
)
=
0
). Moreover, a countable set of spectral singularities on the continuous spectrum can exist which coincides with numbers of the form
λ
=
0
,
λ
s
j
n
=
i
α
n
(
ω
j
−
ω
s
)
−
1
,
n
∈
N
,
s
,
j
=
1
,
2
,
…
,
m
,
j
≠
s
. If
ϕ
(
z
)
=
(
z
−
ω
0
)
m
, then the spectral singularity does not exist. The resolvent
L
λ
−
1
is an integral operator in
L
2
(
R
)
with the kernel of Karleman type for any
λ
∈
ρ
(
L
λ
)
. |
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ISSN: | 1687-2770 1687-2762 1687-2770 |
DOI: | 10.1186/s13661-015-0480-8 |