Internal initiation of polyuridylic acid translation in bacterial cell-free system
The task of the present work was to answer the question: is the free 5′-end needed for effective translation of a model polyribonucleotide template — polyuridylic acid — in a bacterial ( E. coli ) cell-free system? For this purpose, the template activities of the original polyuridylic acid with its...
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Veröffentlicht in: | Biochemistry (Moscow) 2013-12, Vol.78 (12), p.1354-1357 |
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Sprache: | eng |
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Zusammenfassung: | The task of the present work was to answer the question: is the free 5′-end needed for effective translation of a model polyribonucleotide template — polyuridylic acid — in a bacterial (
E. coli
) cell-free system? For this purpose, the template activities of the original polyuridylic acid with its free 5′-end and the polyuridylic acid with blocked 5′-end were compared in the bacterial cell-free translation system. To block the 5′-end, the cytidylic oligodeoxyribonucleotide with fluorescein residue at its 5′-end and uridylic oligoribonucleotide sequence at its 3′-end, schematically described as FAM(dC)
10
(rU)
50
, was covalently attached (ligated) to the 5′-end of the template polyuridylic acid. It was shown that the efficiency of polyphenylalanine synthesis on the 5′-blocked template and on the polyuridylic acid with free 5′-end was virtually the same. It was concluded that bacterial ribosomes are capable of effectively initiating translation at the polyuridylic sequence independently of the 5′-end of template polyribonucleotide, i.e. via an internal initiation mechanism, in the absence of a Shine-Dalgarno sequence and AUG start codon. |
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ISSN: | 0006-2979 1608-3040 |
DOI: | 10.1134/S0006297913120055 |