Bisecting three classes of lines

We consider the following problem: Let \(\mathcal{L}\) be an arrangement of \(n\) lines in \(\mathbb{R}^3\) colored red, green, and blue. Does there exist a vertical plane \(P\) such that a line on \(P\) simultaneously bisects all three classes of points in the cross-section \(\mathcal{L} \cap P\)?...

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Veröffentlicht in:arXiv.org 2019-09
Hauptverfasser: Pilz, Alexander, Schnider, Patrick
Format: Artikel
Sprache:eng
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Zusammenfassung:We consider the following problem: Let \(\mathcal{L}\) be an arrangement of \(n\) lines in \(\mathbb{R}^3\) colored red, green, and blue. Does there exist a vertical plane \(P\) such that a line on \(P\) simultaneously bisects all three classes of points in the cross-section \(\mathcal{L} \cap P\)? Recently, Schnider [SoCG 2019] used topological methods to prove that such a cross-section always exists. In this work, we give an alternative proof of this fact, using only methods from discrete geometry. With this combinatorial proof at hand, we devise an \(O(n^2\log^2(n))\) time algorithm to find such a plane and the bisector of the induced cross-section. We do this by providing a general framework, from which we expect that it can be applied to solve similar problems on cross-sections and kinetic points.
ISSN:2331-8422