On Fermat's marginal note: a suggestion
A suggestion is put forward regarding a partial proof of FLT(case1), which is elegant and simple enough to have caused Fermat's enthusiastic remark in the margin of his Bachet edition of Diophantus' "Arithmetica". It is based on an extension of Fermat's Small Theorem (FST) t...
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Veröffentlicht in: | arXiv.org 2001-03 |
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Format: | Artikel |
Sprache: | eng |
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Zusammenfassung: | A suggestion is put forward regarding a partial proof of FLT(case1), which is elegant and simple enough to have caused Fermat's enthusiastic remark in the margin of his Bachet edition of Diophantus' "Arithmetica". It is based on an extension of Fermat's Small Theorem (FST) to mod p^k for any k>0, and the cubic roots of 1 mod p^k for primes p=1 mod 6. For this solution in residues the exponent p distributes over a sum, which blocks extension to equality for integers, providing a partial proof of FLT case1 for all p=1 mod 6. This simple solution begs the question why it was not found earlier. Some mathematical, historical and psychological reasons are presented. . . . . In a companion paper, on the triplet structure of Arithmetic mod p^k, this cubic root solution is extended to the general rootform of FLT (mod p^k) (case1), called "triplet". While the cubic root solution (a^3=1 mod p^k) involves one inverse pair: a+a^{-1} = -1 mod p^k, a triplet has three inverse pairs in a 3-loop: a+b^{-1} = b+c^{-1} = c+a^{-1} = -1 (mod p^k) where abc = 1 (mod p^k), which reduces to the cubic root form if a=b=c (\neq 1) mod p^k. The triplet structure is not restricted to p-th power residues (for some p \geq 59) but applies to all residues in the group G_k(.) of units in the semigroup of multiplication mod p^k. |
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ISSN: | 2331-8422 |