Rational versus transcendental points on analytic Riemann surfaces
Let ( X , L ) be a polarized variety over a number field K . We suppose that L is an hermitian line bundle. Let M be a non compact Riemann Surface and U ⊂ M be a relatively compact open set. Let φ : M → X ( C ) be a holomorphic map. For every positive real number T , let A U ( T ) be the cardinalit...
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Veröffentlicht in: | Manuscripta mathematica 2022-09, Vol.169 (1-2), p.77-105 |
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Format: | Artikel |
Sprache: | eng |
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Zusammenfassung: | Let (
X
,
L
) be a polarized variety over a number field
K
. We suppose that
L
is an hermitian line bundle. Let
M
be a non compact Riemann Surface and
U
⊂
M
be a relatively compact open set. Let
φ
:
M
→
X
(
C
)
be a holomorphic map. For every positive real number
T
, let
A
U
(
T
)
be the cardinality of the set of
z
∈
U
such that
φ
(
z
)
∈
X
(
K
)
and
h
L
(
φ
(
z
)
)
≤
T
. After a revisitation of the proof of the sub exponential bound for
A
U
(
T
)
, obtained by Bombieri and Pila, we show that there are intervals of the reals such that for
T
in these intervals,
A
U
(
T
)
is upper bounded by a polynomial in
T
. We then introduce subsets of type
S
with respect of
φ
. These are compact subsets of
M
for which an inequality similar to Liouville inequality on algebraic points holds. We show that, if
M
contains a subset of type
S
, then,
for every value of
T
the number
A
U
(
T
)
is bounded by a polynomial in
T
. As a consequence, we show that if
M
is a smooth leaf of an algebraic foliation in curves defined over
K
then
A
U
(
T
)
is bounded by a polynomial in
T
. Let
S
(
X
) be the subset (full for the Lebesgue measure) of points which verify some kind of Liouville inequalities. In the second part we prove that
φ
-
1
(
S
(
X
)
)
≠
∅
if and only if
φ
-
1
(
S
(
X
)
)
is full for the Lebesgue measure on
M
. |
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ISSN: | 0025-2611 1432-1785 |
DOI: | 10.1007/s00229-021-01324-4 |