DC POWER SUPPLY CIRCUIT

PURPOSE:To suppress current consumption by stepping up and down the current, which is supplied from a DC power supply, with a DC amplifier circuit, and feeding back the current into the DC amplifier circuit again after a load circuit is operated with this potential. CONSTITUTION:In this circuit, a DC/DC converter (DD) 2 is included, the positive output side thereof and the upstepped-up input side are connected and a closed loop is constituted. A load circuit 3 is provided in the closed loop. The voltage is stepped up with the DD 2 by the value corresponding to the voltage drop caused by the load circuit 3. The voltage is applied on the positive side of the load circuit 3. The current, which has passed through the load circuit 3, is fed back to the DD 2 again. For example, when the potential of both electrodes of the DC power supply 1 is made to be V1 and the potential stepped up with the DD 2 is made to be V2, the potential difference V3 between the positive output of the DD 2 and the unstepped-up input is expressed by V2-V1. Thus, the balance of the potential is kept at a point (c). In this way, the load circuit 3 is operated by the same way as in the conventional circuit.