METHOD FOR EVALUATING SHEAR STRENGTH OF BEAM WITH SLAB AND STRUCTURE

To provide a method for evaluating the shear strength of a beam with a slab.SOLUTION: In a beam 30 with a slab comprising of a beam lower part 11 made of first concrete, a beam upper part 12 made of second concrete, and a slab 20, when the design reference strength of the first concrete is Fcd [N/mm...

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Hauptverfasser: ISHIWATARI YASUHIRO, SASAI KAZUYA, HAGA YUJI, HANYUDA TAKENARI, SUZUKI MINERI, IWABUCHI TAKAYUKI, MAEJIMA KATSURO, NOBATA SHIGEO, KISHIMOTO TAKESHI, AKABOSHI HIROHITO, HAMADA MAKOTO, OIFUJI SHINYA, MORI KOJI
Format: Patent
Sprache:eng ; jpn
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Zusammenfassung:To provide a method for evaluating the shear strength of a beam with a slab.SOLUTION: In a beam 30 with a slab comprising of a beam lower part 11 made of first concrete, a beam upper part 12 made of second concrete, and a slab 20, when the design reference strength of the first concrete is Fcd [N/mm2], the design reference strength of the second concrete is Fcu [N/mm2], the cross-sectional area of the beam lower part 11 is Ad [mm2], the cross-sectional area of the beam upper part 12 is Au [mm2], the cooperation width of the slab 20 is ba [mm], the thickness of the slab 20 is t [mm], the height of the beam upper part 12 is Tu [mm], and the width of the beam 10 is b [mm], the average strength Fce [N/mm2] of the concrete in evaluating the shear strength of the beam 30 with the slab is expressed by the formula: Fce=(Fcd×Ad + αs×Fcu×Au)/(Ad + Au) ...(1), and the overdesign factor αs in the formula (1) is expressed by the formula: αs=1 + t '×b' ...(2), where t '=t/Tu, b'=ba/b.SELECTED DRAWING: Figure 2 【課題】スラブ付き梁のせん断強度評価方法を提供する。【解決手段】第1のコンクリートによる梁下部11と、第2のコンクリートによる梁上部12及びスラブ20とからなるスラブ付き梁30において、第1のコンクリートの設計基準強度をFcd[N/mm2]、第2のコンクリートの設計基準強度をFcu[N/mm2]、梁下部11の断面積をAd[mm2]、梁上部12の断面積をAu[mm2]、スラブ20の協力幅をba[mm]、スラブ20の厚さをt[mm]、梁上部12の高さをTu[mm]、梁10の幅をb[mm]としたとき、スラブ付き梁30のせん断強度を評価する際のコンクリートの平均強度Fce[N/mm2]は、Fce=(Fcd・Ad+αs・Fcu・Au)/(Ad+Au)・・・式(1)で表され、式(1)における割増係数αsは、αs=1+t'・b'・・・式(2)で表される。ここで、t'=t/Tu、b'=ba/bである。【選択図】図2