Formula of high-temperature-resistant flame-retardant engineering plastics

The invention discloses a formula of high-temperature-resistant flame-retardant engineering plastics. The formula comprises the following raw materials in parts by mass: 50-60 parts of polycarbonate,10-15 parts of polystyrene, 10-12 parts of polybutadiene, 5-8 parts of polytetrafluoroethylene, 2-4 p...

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Bibliographische Detailangaben
Hauptverfasser: PAN SHUGANG, ZHANG NING, DAI WEIMIN, TENG YEFANG
Format: Patent
Sprache:chi ; eng
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Zusammenfassung:The invention discloses a formula of high-temperature-resistant flame-retardant engineering plastics. The formula comprises the following raw materials in parts by mass: 50-60 parts of polycarbonate,10-15 parts of polystyrene, 10-12 parts of polybutadiene, 5-8 parts of polytetrafluoroethylene, 2-4 parts of stearic acid, 2-3 parts of antioxidant, 0.3-0.5 part of silane coupler, 3-4 parts of flameretardant and 0.5-1 part of antistat. The formula of the high-temperature-resistant flame-retardant engineering plastics, disclosed by the invention, is scientific and reasonable, and engineering plastic products prepared by the formula are resistant to high temperatures, can resist a high temperature as high as 250 DEG C, are excellent in quality and are durable. 本发明公开了种抗高温阻燃工程塑料配方,原料的质量份数组成如下:聚碳酸酯50-60份、聚苯乙烯10-15份、聚丁二烯10-12份、聚四氟乙烯5-8份、硬脂酸2-4份、抗氧剂2-3份、硅烷偶联剂0.3-0.5份、阻燃剂3-4份、抗静电剂0.5-1份,本发明种抗高温阻燃工程塑料配方科学合理,经此配方制得的工程塑料产品抗高温,可耐高达250℃的高温,质量优异,经久耐用。