Corrigendum: Estimating the Minimal Number of Repeated Examinations for Random Responsiveness With the Coma Recovery Scale—Revised as an Example

A correction has been made to Materials and methods, Development of statistical formulas, Data and formulas, Paragraph 2: Since both of a1/n and any of the formulas in the 5-th column of Table 1 approximate to the same probability of positive response to a single examination given by a MCS patient, we have a1n≈a1+a2n+(n−a1),a1n≈a1+a2+a3n+(n−a1)+(n−a1−a2) a1n≈a1+a2n+(n-a1),a1n≈a1+a2+a3n+(n-a1)+(n-a1-a2) and a1n≈a1+⋯+ain+(n−a1)+⋯(n−a1−⋯−ai−1) a1n≈a1+⋯+ain+(n-a1)+⋯(n-a1-⋯-ai-1) Denote their solutions of n, respectively, by nˆ2≈a21a1−a2, nˆ3≈a1(2a1+a2)2a1−a2−a3 n^2≈a12a1-a2, n^3≈a1(2a1+a2)2a1-a2-a3 and nˆi≈a1[(i−1)a1+(i−2)a2+⋯+ai−1](i−1)a1−a2−⋯−ai, pˆi=a1nˆi n^i≈a1[(i-1)a1+(i-2)a2+⋯+ai-1](i-1)a1-a2-⋯-ai, p^i=a1n^i These formulas have been summarized in Table 2. After completing the 5-th round, we obtained a5 = 0, and nˆ5=a1(4a1+3a2+2a3+a4)4a1−a2−a3−a4−a5=29×130110=34.27,pˆ5≈a1nˆ5=2934.27=0.8462 n^5=a1(4a1+3a2+2a3+a4)4a1-a2-a3-a4-a5=29×130110=34.27,p^5≈a1n^5=2934.27=0.8462 Since (1−pˆ5)5=0.000086