Co-Absolutes with Homeomorphic Dense Subspaces
Recall that the absolute ∈(X) of a regular space X is the unique (up to a homeomorphism) extremally disconnected space whose image is X under a perfect irreducible map. X and Y are co-absolute whenever ∈(X) and ∈(Y) are homeomorphic. Completely regular spaces X and Y are weakly co-absolute whenever...
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Veröffentlicht in: | Canadian journal of mathematics 1981-08, Vol.33 (4), p.857-861 |
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Sprache: | eng |
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Zusammenfassung: | Recall that the absolute ∈(X) of a regular space X is the unique (up to a homeomorphism) extremally disconnected space whose image is X under a perfect irreducible map. X and Y are co-absolute whenever ∈(X) and ∈(Y) are homeomorphic. Completely regular spaces X and Y are weakly co-absolute whenever βX and βY are co-absolute. For a survey of this area we suggest [6] and [8]. In this paper we prove THEOREM 1. Suppose, for i ∈ {0, 1};, X(i) is a compact connected linearly ordered space. Then X(0) and X(l) are co-absolute if, and only if, X(0) and X(l) have homeomorphic dense sets.
Making use of Theorem 1 and a result from [7] we give Theorem 2, a cardinal generalization of COROLLARY 1. Suppose for each i ∈ {0, 1};, X(i) is a Čech-complete space with a Gδ-diagonal. |
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ISSN: | 0008-414X 1496-4279 |
DOI: | 10.4153/CJM-1981-066-1 |