Nonintersecting subspaces based on finite alphabets
Two subspaces of a vector space are here called "nonintersecting" if they meet only in the zero vector. Motivated by the design of noncoherent multiple-antenna communications systems, we consider the following question. How many pairwise nonintersecting M/sub t/-dimensional subspaces of an...
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Veröffentlicht in: | IEEE transactions on information theory 2005-12, Vol.51 (12), p.4320-4325 |
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Sprache: | eng |
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Zusammenfassung: | Two subspaces of a vector space are here called "nonintersecting" if they meet only in the zero vector. Motivated by the design of noncoherent multiple-antenna communications systems, we consider the following question. How many pairwise nonintersecting M/sub t/-dimensional subspaces of an m-dimensional vector space V over a field F can be found, if the generator matrices for the subspaces may contain only symbols from a given finite alphabet A/spl sube/F? The most important case is when F is the field of complex numbers C; then M/sub t/ is the number of antennas. If A=F=GF(q) it is shown that the number of nonintersecting subspaces is at most (q/sup m/-1)/(q/sup Mt/-1), and that this bound can be attained if and only if m is divisible by M/sub t/. Furthermore, these subspaces remain nonintersecting when "lifted" to the complex field. It follows that the finite field case is essentially completely solved. In the case when F=C only the case M/sub t/=2 is considered. It is shown that if A is a PSK-configuration, consisting of the 2/sup r/ complex roots of unity, the number of nonintersecting planes is at least 2/sup r(m-2)/ and at most 2/sup r(m-1)-1/ (the lower bound may in fact be the best that can be achieved). |
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ISSN: | 0018-9448 1557-9654 |
DOI: | 10.1109/TIT.2005.858946 |