Distribution modulo one and denominators of the Bernoulli polynomials
Let $\{\cdot\}$ denote the fractional part and $n \geq 1$ be a fixed integer. In this short note, we show for any prime $p$ the one-to-one correspondence $$\sum_{\nu \geq 1} \left\{\frac{n}{p^\nu}\right\} > 1 \quad \iff \quad p \mid \mathrm{denom}( B_n(x) - B_n ),$$ where $B_n(x) - B_n$ is the $n...
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Zusammenfassung: | Let $\{\cdot\}$ denote the fractional part and $n \geq 1$ be a fixed integer.
In this short note, we show for any prime $p$ the one-to-one correspondence
$$\sum_{\nu \geq 1} \left\{\frac{n}{p^\nu}\right\} > 1 \quad \iff \quad p \mid
\mathrm{denom}( B_n(x) - B_n ),$$ where $B_n(x) - B_n$ is the $n$th Bernoulli
polynomial without constant term and $\mathrm{denom}(\cdot)$ is its
denominator, which is squarefree. |
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DOI: | 10.48550/arxiv.1708.07119 |