Lyndon words and Fibonacci numbers
It is a fundamental property of non-letter Lyndon words that they can be expressed as a concatenation of two shorter Lyndon words. This leads to a naive lower bound log_{2}(n)} + 1 for the number of distinct Lyndon factors that a Lyndon word of length n must have, but this bound is not optimal. In t...
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creator | Saari, Kalle |
description | It is a fundamental property of non-letter Lyndon words that they can be
expressed as a concatenation of two shorter Lyndon words. This leads to a naive
lower bound log_{2}(n)} + 1 for the number of distinct Lyndon factors that a
Lyndon word of length n must have, but this bound is not optimal. In this paper
we show that a much more accurate lower bound is log_{phi}(n) + 1, where phi
denotes the golden ratio (1 + sqrt{5})/2. We show that this bound is optimal in
that it is attained by the Fibonacci Lyndon words. We then introduce a mapping
L_x that counts the number of Lyndon factors of length at most n in an infinite
word x. We show that a recurrent infinite word x is aperiodic if and only if
L_x >= L_f, where f is the Fibonacci infinite word, with equality if and only
if f is in the shift orbit closure of f. |
doi_str_mv | 10.48550/arxiv.1207.4233 |
format | Article |
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expressed as a concatenation of two shorter Lyndon words. This leads to a naive
lower bound log_{2}(n)} + 1 for the number of distinct Lyndon factors that a
Lyndon word of length n must have, but this bound is not optimal. In this paper
we show that a much more accurate lower bound is log_{phi}(n) + 1, where phi
denotes the golden ratio (1 + sqrt{5})/2. We show that this bound is optimal in
that it is attained by the Fibonacci Lyndon words. We then introduce a mapping
L_x that counts the number of Lyndon factors of length at most n in an infinite
word x. We show that a recurrent infinite word x is aperiodic if and only if
L_x >= L_f, where f is the Fibonacci infinite word, with equality if and only
if f is in the shift orbit closure of f.</description><identifier>DOI: 10.48550/arxiv.1207.4233</identifier><language>eng</language><subject>Computer Science - Discrete Mathematics ; Mathematics - Combinatorics</subject><creationdate>2012-07</creationdate><rights>http://arxiv.org/licenses/nonexclusive-distrib/1.0</rights><oa>free_for_read</oa><woscitedreferencessubscribed>false</woscitedreferencessubscribed></display><links><openurl>$$Topenurl_article</openurl><openurlfulltext>$$Topenurlfull_article</openurlfulltext><thumbnail>$$Tsyndetics_thumb_exl</thumbnail><link.rule.ids>228,230,780,885</link.rule.ids><linktorsrc>$$Uhttps://arxiv.org/abs/1207.4233$$EView_record_in_Cornell_University$$FView_record_in_$$GCornell_University$$Hfree_for_read</linktorsrc><backlink>$$Uhttps://doi.org/10.48550/arXiv.1207.4233$$DView paper in arXiv$$Hfree_for_read</backlink></links><search><creatorcontrib>Saari, Kalle</creatorcontrib><title>Lyndon words and Fibonacci numbers</title><description>It is a fundamental property of non-letter Lyndon words that they can be
expressed as a concatenation of two shorter Lyndon words. This leads to a naive
lower bound log_{2}(n)} + 1 for the number of distinct Lyndon factors that a
Lyndon word of length n must have, but this bound is not optimal. In this paper
we show that a much more accurate lower bound is log_{phi}(n) + 1, where phi
denotes the golden ratio (1 + sqrt{5})/2. We show that this bound is optimal in
that it is attained by the Fibonacci Lyndon words. We then introduce a mapping
L_x that counts the number of Lyndon factors of length at most n in an infinite
word x. We show that a recurrent infinite word x is aperiodic if and only if
L_x >= L_f, where f is the Fibonacci infinite word, with equality if and only
if f is in the shift orbit closure of f.</description><subject>Computer Science - Discrete Mathematics</subject><subject>Mathematics - Combinatorics</subject><fulltext>true</fulltext><rsrctype>article</rsrctype><creationdate>2012</creationdate><recordtype>article</recordtype><sourceid>GOX</sourceid><recordid>eNotzj0LwjAUheEsDqLuTlLcW5PcJKajiFWh4NK93CQNFDSVFD_676XqdN7p8BCyZDQTWkq6wfhunxnjdJsJDjAl63IIrgvJq4uuTzC4pGhNF9DaNgmPm2liPycTj9e-Wfx3RqriUO1PaXk5nve7MkUlIfWoPaeKKka3yoADxnJkTcO9kc5w4H5sm3uUPFdKCgUMtRFUc-O1sDAjq9_t11jfY3vDONSjtR6t8AGvYjf4</recordid><startdate>20120717</startdate><enddate>20120717</enddate><creator>Saari, Kalle</creator><scope>AKY</scope><scope>AKZ</scope><scope>GOX</scope></search><sort><creationdate>20120717</creationdate><title>Lyndon words and Fibonacci numbers</title><author>Saari, Kalle</author></sort><facets><frbrtype>5</frbrtype><frbrgroupid>cdi_FETCH-LOGICAL-a653-fa8f206061076b3d3119a1ee2fb5db232fee2fc9fa5296654631a8b4082bf84c3</frbrgroupid><rsrctype>articles</rsrctype><prefilter>articles</prefilter><language>eng</language><creationdate>2012</creationdate><topic>Computer Science - Discrete Mathematics</topic><topic>Mathematics - Combinatorics</topic><toplevel>online_resources</toplevel><creatorcontrib>Saari, Kalle</creatorcontrib><collection>arXiv Computer Science</collection><collection>arXiv Mathematics</collection><collection>arXiv.org</collection></facets><delivery><delcategory>Remote Search Resource</delcategory><fulltext>fulltext_linktorsrc</fulltext></delivery><addata><au>Saari, Kalle</au><format>journal</format><genre>article</genre><ristype>JOUR</ristype><atitle>Lyndon words and Fibonacci numbers</atitle><date>2012-07-17</date><risdate>2012</risdate><abstract>It is a fundamental property of non-letter Lyndon words that they can be
expressed as a concatenation of two shorter Lyndon words. This leads to a naive
lower bound log_{2}(n)} + 1 for the number of distinct Lyndon factors that a
Lyndon word of length n must have, but this bound is not optimal. In this paper
we show that a much more accurate lower bound is log_{phi}(n) + 1, where phi
denotes the golden ratio (1 + sqrt{5})/2. We show that this bound is optimal in
that it is attained by the Fibonacci Lyndon words. We then introduce a mapping
L_x that counts the number of Lyndon factors of length at most n in an infinite
word x. We show that a recurrent infinite word x is aperiodic if and only if
L_x >= L_f, where f is the Fibonacci infinite word, with equality if and only
if f is in the shift orbit closure of f.</abstract><doi>10.48550/arxiv.1207.4233</doi><oa>free_for_read</oa></addata></record> |
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subjects | Computer Science - Discrete Mathematics Mathematics - Combinatorics |
title | Lyndon words and Fibonacci numbers |
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