On Galois realizations of the 2-coverable symmetric and alternating groups
Let f(x) be a monic polynomial in Z[x] with no rational roots but with roots in Q_p for all p, or equivalently, with roots mod n for all n. It is known that f(x) cannot be irreducible but can be a product of two or more irreducible polynomials, and that if f(x) is a product of m>1 irreducible pol...
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Zusammenfassung: | Let f(x) be a monic polynomial in Z[x] with no rational roots but with roots
in Q_p for all p, or equivalently, with roots mod n for all n. It is known that
f(x) cannot be irreducible but can be a product of two or more irreducible
polynomials, and that if f(x) is a product of m>1 irreducible polynomials, then
its Galois group must be "m-coverable", i.e. a union of conjugates of m proper
subgroups, whose total intersection is trivial. We are thus led to a variant of
the inverse Galois problem: given an m-coverable finite group G, find a Galois
realization of G over the rationals Q by a polynomial f(x) in Z[x] which is a
product of m nonlinear irreducible factors (in Q[x]) such that f(x) has a root
in Q_p for all p. The minimal value m=2 is of special interest. It is known
that the symmetric group S_n is 2-coverable if and only if 2 |
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DOI: | 10.48550/arxiv.1008.3061 |