Common Invariant Subspace and Commuting Matrices
Let $K$ be a perfect field, $L$ be an extension field of $K$ and $A,B\in\mathcal{M}_n(K)$. If $A$ has $n$ distinct eigenvalues in $L$ that are explicitly known, then we can check if $A,B$ are simultaneously triangularizable over $L$. Now we assume that $A,B$ have a common invariant proper vector sub...
Gespeichert in:
1. Verfasser: | |
---|---|
Format: | Artikel |
Sprache: | eng |
Schlagworte: | |
Online-Zugang: | Volltext bestellen |
Tags: |
Tag hinzufügen
Keine Tags, Fügen Sie den ersten Tag hinzu!
|
Zusammenfassung: | Let $K$ be a perfect field, $L$ be an extension field of $K$ and
$A,B\in\mathcal{M}_n(K)$. If $A$ has $n$ distinct eigenvalues in $L$ that are
explicitly known, then we can check if $A,B$ are simultaneously
triangularizable over $L$.
Now we assume that $A,B$ have a common invariant proper vector subspace of
dimension $k$ over an extension field of $K$ and that $\chi_A$, the
characteristic polynomial of $A$, is irreducible over $K$. Let $G$ be the
Galois group of $\chi_A$. We show the following results i) If $k\in{1,n-1}$,
then $A,B$ commute. ii) If $1\leq k\leq n-1$ and $G=\mathcal{S}_n$ or
$G=\mathcal{A}_n$, then $AB=BA$. iii) If $1\leq k\leq n-1$ and $n$ is a prime
number, then $AB=BA$. Yet, when $n=4,k=2$, we show that $A,B$ do not
necessarily commute if $G$ is not $\mathcal{S}_4$ or $\mathcal{A}_4$. Finally
we apply the previous results to solving a matrix equation. |
---|---|
DOI: | 10.48550/arxiv.1206.3630 |